i m sorry i have not any notepad to remedy it . yet i am going to tell u a thanks to.. from equation 6(x+2)-5y=ninety ,, evaluate the cost the cost of y ,, it will be y={6(x+2)-ninety}/5 . now placed it in to 1st equation . calculate the cost of x . then placed it into y={6(x+2)-ninety}/5 to confirm y to discover equation of circle , use formula ' total sq. root of (x-h)sq.+(y-ok)sq. ' = radius sq. . h and ok will be 0 (as middle is at origon) . to discover the point interior or out circle ,, placed it into the gained equation of circle . if answer > o , then its outdoors . if answer < o ,, then its interior make sure the solutions with another source too
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http://www.math.uakron.edu/~dpstory/mpt_home.html
http://teachers.henrico.k12.va.us/math/HCPSAlgebra...
http://www.math.tntech.edu/machida/MATH_GO/Precalc...
i m sorry i have not any notepad to remedy it . yet i am going to tell u a thanks to.. from equation 6(x+2)-5y=ninety ,, evaluate the cost the cost of y ,, it will be y={6(x+2)-ninety}/5 . now placed it in to 1st equation . calculate the cost of x . then placed it into y={6(x+2)-ninety}/5 to confirm y to discover equation of circle , use formula ' total sq. root of (x-h)sq.+(y-ok)sq. ' = radius sq. . h and ok will be 0 (as middle is at origon) . to discover the point interior or out circle ,, placed it into the gained equation of circle . if answer > o , then its outdoors . if answer < o ,, then its interior make sure the solutions with another source too