No, - of course not. If that were correct then a graph of clinically recorded SV's plotted against what you are calling 'arterial pressure' would produce a straight-line curve, of the form {y=mx +c}, and it doesn't.. It's easy to check; just do it and see.
In reality, irrespective of whether you plot stroke volume or cardiac output against whatever pressure you are calling "arterial pressure", it never comes out as a straight-line graph. It comes out always quite random. You can get high arterial pressure with low stroke volumes and/or low arterial pressures with high stroke volumes, (and any combinations in between, medium, high, or lows, - whatever) .
Because it all hinges on what the simultaneous pulse-rate does.
- For instance, if cardiac output drops from 5L/min to 4L/min and at the same time pulse rate falls from 80 bpm to 60 bpm the "arterial pressure" will actually rise, -not fall, and the greater the fall in heart rate, the larger the rise in pressure becomes. In fact, pressure rises parabolically, not linearly, with falling pulse-rate, once the critical point is reached.
But there is actually a precise relationship between arterial pressures, pulse rate, and cardiac output, expressible as a (relatively) simple algebraic equation, which explains the mechanism at work.
Cardio overlooks the fact that TPR decreases in direct proportion to cardiac output, and that it is possible for any specific cardiac output to be achieved by an infinite number of combinations of stroke volumes and pulse rates.
Would that the cardiovascular world was so simple and uncomplicated as that !
Then all one would need to do is reduce TPR, Pulse rate, and cardiac output to zero..... and so, (despite the patient being dead) the problem of "high blood pressure" would be solved, at one stroke (no pun intended!).
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No, - of course not. If that were correct then a graph of clinically recorded SV's plotted against what you are calling 'arterial pressure' would produce a straight-line curve, of the form {y=mx +c}, and it doesn't.. It's easy to check; just do it and see.
In reality, irrespective of whether you plot stroke volume or cardiac output against whatever pressure you are calling "arterial pressure", it never comes out as a straight-line graph. It comes out always quite random. You can get high arterial pressure with low stroke volumes and/or low arterial pressures with high stroke volumes, (and any combinations in between, medium, high, or lows, - whatever) .
Because it all hinges on what the simultaneous pulse-rate does.
- For instance, if cardiac output drops from 5L/min to 4L/min and at the same time pulse rate falls from 80 bpm to 60 bpm the "arterial pressure" will actually rise, -not fall, and the greater the fall in heart rate, the larger the rise in pressure becomes. In fact, pressure rises parabolically, not linearly, with falling pulse-rate, once the critical point is reached.
But there is actually a precise relationship between arterial pressures, pulse rate, and cardiac output, expressible as a (relatively) simple algebraic equation, which explains the mechanism at work.
You can find it published, on my website.
Cardio overlooks the fact that TPR decreases in direct proportion to cardiac output, and that it is possible for any specific cardiac output to be achieved by an infinite number of combinations of stroke volumes and pulse rates.
Would that the cardiovascular world was so simple and uncomplicated as that !
Then all one would need to do is reduce TPR, Pulse rate, and cardiac output to zero..... and so, (despite the patient being dead) the problem of "high blood pressure" would be solved, at one stroke (no pun intended!).
yes it does.
stroke volume * heart rate = cardiac output
cardiac output * peripheral vascular resistance = blood pressure
so therefore stroke volume * heart rate * peripheral vascular resistance = blood pressure
so in conclusion a reduction in stroke volume, or heart rate or PVR will decrease blood pressure
If the heart isn't pumping as quickly, blood pressure goes down, just the mean arterial pressure would go down.