Verified answer

1) Distribute:

4x-2-y+4=11

3-3x-2y+6=-7

2) lets solve the first one for y

4x-2-y+4=11

-y=11-4+2-4x Multiply both sides by (-1)

y=-11+4-2+4x

y= -9+ 4x

3)substitute on the second equation

3-3x-2y+6=-7

3 - 3x -2 (-9+4x)+6 = -7 and then solve for x

3-3x +18 - 8x +6 = -7

-11x = -7 -6 -3-18

-11x= -34 both sides X (-1)

11x=34

x=34/11

and substitute the value of x on either equations to get the value of y

First, distribute:

4x-2-y+4 = 11

3-3x-2y+6 = -7

Then, combine like terms:

4x - y +2 =11

-3x -2y +9 = -7

Then move all constants to one side, leaving variables on the other:

4x -y = 9

-3x -2y = -16

Then multiply one line to cancel out one variable:

(4x-y = 9) X -2

Giving you:

-8X + 2y = -18

-3x -2y = -16

The 2y's cancel, giving you

-8x = -18

-3x = -16

_______

-11x = -34

x = 34/11

Then plug x into one of the original equations (4x - y = 9, for example) to solve for y

2(2x-1)-(y-4)=11

4x-2-y+4=11

4x-y=9

-y=-4x+9

y=4x-9

4x-(-4x+9)=9

4x+4x-9=9

8x=18

x=9/4(answer)

y=4x-9

y=4(9/4)-9

y=0(answer)

Therefore, x=9/4 and y=0.

You use the same method to do the second one!!!