Verified answer

A) log √(125/8)

= log √(5³/2³) = log [5^(3/2)/2^(3/2)] = log 5^(3/2) - log 2^(3/2) =

= (3/2) . log 5 - (3/2) . log 2 = (3/2) . log (10/2) - (3/2) . 0,301 =

= (3/2) . log 10 - (3/2) . log 2 - (3/2) . log 2 - 0,4515 =

= (3/2) . 1 - (3/2) . 0,301 - 0,4515 = 1,5 - 0,4515 - 0,4515 =

= 0,597

ou

log [√(125)/8)]

= log [√(5³)/2³)] = log [5^(3/2)/2³] = log 5^(3/2) - log 2³ = (3/2) . log 5 - 3 . log 2 =

= (3/2) . log (10/2) - 3 . 0,301 = (3/2) . log 10 - (3/2) . log 2 - 3 . 0,301 =

= (3/2) . 1 - (3/2) . 0,301 - 0,903 = 1,5 - 0,4515 - 0,903 =

= 0,1455

B) log ³√(2 . 10^-5)

= log [2^(1/3) . (10^-5)^(1/3)] = log [2^(1/3) . (10^(-5/3)] = log 2^(1/3) + log 10^(-5/3) =

= (1/3). log 2 + (-5/3). log 10 = (1/3). 0,301 + (-5/3). 1 = 0,1003333 - 1,6666666

= -1,5663333...

ou

log [³√(2) . (10^-5)]

= log ³√(2) + log 10^(-5) = log 2^(1/3) + log 10^(-5) = (1/3) . log 2 + (-5) . log 10 =

= (1/3) . 0,301 + (-5) . 1 = 0,1003333 - 5 =

= -4,899666...