7th grade math problem?
At a committee meeting, ten people were seated around a circular table. At the conclusion of the meeting, each person shook hands with everyone else at the meeting except the people who sat either to the right or to the left. How many handshakes took place?
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Draw a circular table. Then number the people, one through ten.
Number one person shakes hands with people numbered three through nine.
Of the ten people at the committee meeting, the first one shakes hands with seven others.
The number two person shakes hands with people numbered four through ten, a total of seven others.
The third one shakes hands with six others, because she/he already shook hands with #1 person.
Similarly, the number four person one shakes hands with five others, because he/she already shook #1,2
The fifth one shakes hands with four others
The sixth one shakes hands with three others
The seventh one shakes hands with two others
The eighth one shakes hands with one other.
And ninth and tenth people have already shaken hands with the others.
Adding all the handshakes = 7 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 35 non-repeating handshakes
well to work this question out I drew 10 people around a circle. I then drew lines from one person to everyone else in the circle except for the 1 person on the left and 1 person on the right of them. I got an answer of 7 handshakes. As there is 10 people, multiply this number (7) by the total (10) and you get an answer of 70 handshakes :)
1 PERSON SHAKES HANDS WITH 7 PERSONS
10 PERSONS = 10 x 7 = 70
70/2 = 35 HANDSHAKES answer
okay, lets suppose you only had to find out how many handshakes one person had at the meeting.
that one person doesn't count so 10-1=9
the people directly right and left to him don't count so 9-2=7
okay so one person at that meeting shook seven hands, multiply that by ten and you've got
70, unless i had brain fart or i completely overlooked something i'm guessing its that.
60?