Verified answer

You've got it right so far.

You want to take the 3x from 3x(2x+5) and combine it with the +2 from +2(2x+5)

So know it factors into (3x+2)(2x+5)

and if you are looking for the solutions just set both =0 and solve

3x+2=0 x=(-2/3)

2x+5=0 x=(-5/2)

Hopefully that helps

Both the 3x and the 2 are being multiplied by 2x+5, so you can just multiply 2x+5 by the sum of 3x and 2. So, the answer would be (2x+5)(3x+2).

Here's another way of thinking about it in case that isn't clear. Let y be 2x+5. Then the expression becomes 3xy+2y. Factoring out the y, you get y(3x+2). Then rewriting y as 2x+5, you get (2x+5)(3x+2), which is the same as before.

Hope that helps :)

think of approximately it this form, (8x^2 - 20x) - a million(2x - 5) = 0 we might prefer to component out some term/s so as that (8x^2 - 20x) and -(2x - 5) will exchange into the comparable term. we gained't component -(2x - 5) any further, inspite of the actuality that it has a coefficient of -a million, yet we are able to component out 4x from (8x^2 - 20x). we are going to be left with 4x(2x - 5) -a million(2x - 5 ) = 0 4x(2x - 5) - a million(2x - 5) = 0, could be rewritten as, (4x - a million)(2x - 5) = 0 So, 8x^2 - 22x + 5 could be factored as (4x - a million)(2x - 5). fixing for x, If, (4x - a million)(2x - 5 ) = 0, then a minimum of between the words might desire to equivalent 0. so if, (4x - a million) = 0 then x = a million / 4 and if (2x - 5 ) = 0 then x = 5 / 2 Plug the x values into the unique quadratic 8x^2 - 22x + 5 to ascertain in the event that they are ultimate.

3x*(2x+5) +2*(2x+5) is easier than you think. Just factor out the like term, which is (2x+5). It may be easier is we simplify it. If a = 2x+5, then your equation looks like 3x*a+2*a right? Which is the same as saying a*(3x+2). Replace the term and you'll see that 3x*(2x+5) +2*(2x+5) = (3x+2)(2x+5)

if you had 3xa + 2a

you'd factor out the a and set it outside the parentheses around

the (3x + 2) that's left behind, giving you

(3x + 2)a

so you do the same with the binomial:

3x(2x + 5) + 2(2x + 5) =

(3x + 2)(2x + 5)