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That doesn't factor in rational numbers. If you allow irrationals you can say:

(x + (7 +√ 85)/2) (x + (7 - √ 85)/2)

but that seems like a lot of trouble when looking for asymptotes.

Can you try another approach?

Can't factor, use other methods instead :

Question Number 1 :

For this equation x^2 + 7*x + 9 = 0 , answer the following questions :

A. Find the roots using Quadratic Formula !

B. Use completing the square to find the root of the equation !

Answer Number 1 :

The equation x^2 + 7*x + 9 = 0 is already in a*x^2+b*x+c=0 form.

By matching the constant position, we can derive that the value of a = 1, b = 7, c = 9.

1A. Find the roots using Quadratic Formula !

Use the formula,

x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a)

Since a = 1, b = 7 and c = 9,

then the value a,b and c in the abc formula, can be subtituted.

Which produce x1 = (-(7) + sqrt( (7)^2 - 4 * (1)*(9)))/(2*1) and x2 = (-(7) - sqrt( (7)^2 - 4 * (1)*(9)))/(2*1)

Which make x1 = ( -7 + sqrt( 49-36))/(2) and x2 = ( -7 - sqrt( 49-36))/(2)

Which is the same as x1 = ( -7 + sqrt( 13))/(2) and x2 = ( -7 - sqrt( 13))/(2)

So we get x1 = ( -7 + 3.60555127546399 )/(2) and x2 = ( -7 - 3.60555127546399 )/(2)

So we have the answers x1 = -1.69722436226801 and x2 = -5.30277563773199

1B. Use completing the square to find the root of the equation !

x^2 + 7*x + 9 = 0 ,divide both side with 1

So we get x^2 + 7*x + 9 = 0 ,

The coefficient of x is 7

We have to use the fact that ( x + q )^2 = x^2 + 2*q*x + q^2 , and assume that q = 7/2 = 3.5

So we have make the equation into x^2 + 7*x + 12.25 - 3.25 = 0

So we will get ( x + 3.5 )^2 - 3.25 = 0

Which is the same with (( x + 3.5 ) - 1.80277563773199 ) * (( x + 3.5 ) + 1.80277563773199 ) = 0

And it is the same with ( x + 3.5 - 1.80277563773199 ) * ( x + 3.5 + 1.80277563773199 ) = 0

And it is the same with ( x + 1.69722436226801 ) * ( x + 5.30277563773199 ) = 0

So we have the answers x1 = -1.69722436226801 and x2 = -5.30277563773199

phythagoream (sp?) theorum. Google it and plug in the numbers. I'm drunk and didn't think about much but I don't think you can factor it with whole numbers.